Chemical basis of pharmacology; an introduction to pharmacodynamics based on the study of the carbon compounds - Softcover

Francis Francis

9781231321959: Chemical basis of pharmacology; an introduction to pharmacodynamics based on the study of the carbon compounds

Softcover

ISBN 10: 1231321954 ISBN 13: 9781231321959

Publisher: Rarebooksclub.com, 2012

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1908 Excerpt: ...however, may be obtained by the action of ammonia on the corresponding halogen derivative, C�H5CH2Cl, that is by a reaction analogous to that which takes place with the aliphatic halogen substitution products. 3. Amido compounds result from the reduction of the nitro derivatives of either aliphatic or aromatic series. But this method of preparation is entirely confined to the latter hydrocarbons, owing to the ease with which the nitro substitution products of this series are obtained. Nitro-benzene, for instance, is reduced to aniline on a commercial scale by means of iron and hydrochloric acid--C6H6N02 + 6H = C6H6NH2 + 2H2O. Secondary amines of the aromatic series may be obtained from the acetyl derivatives of the primary. Thus aniline heated with acetic acid gives acetanilide, C6H6NH;Hj + CH8COlOHi = H2O +C6H6NH(COCH3), and when this substance is acted upon by sodium in an indifferent solvent, such as toluene, the corresponding sodium derivative is obtained, C6H6NH(COCHs) + Na = H + C6H6NCIj3 This readily reacts with an aliphatic halogen derivative giving the corresponding alkyl-acetanilide, which on treatment with potash is broken down into the secondary amine and acetic acid, L CeHc5cH3 + CAI = NaI + C6H6Ng5Hc6H3 ii. C6H6NH +KOH = C6H6NHC2H6 + CH3COOK 3 Ethyl aniline. 4. Acid amides of the aliphatic series on treatment with bromine or potash give amines containing one less carbon atom. The first phase of the reaction consists in the formation of bromamides, CH3CONH2 + Br2 + KOH = CH3CONHBr + KBr + H2O These derivatives are then further broken down into amines, CH3CONHBr + 3KOH = KBr + K2CO3 + CH3NH2 Methylamine. This method is applicable to the amides of the fatty series up to those containing five carbon atoms. In the aromatic series this reaction...

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