This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1883 Excerpt: ...box, for joining spring mouldings may be obtained as follows: If we make B Fig. 116, the moulding showing the spring or lean of the member, and D E the mitre required, then proceed as follows: With A as a centre, and the radius A G, describe the semicircle F H G C; then drop perpendiculars from the line F C, at the points F, A, H, G and c, cutting the mitre line as shown on the line 1 D. Draw 1 E parallel to F C, then from 1 draw i s, which will be the bevel for the side of the box, and the 'bevel o R will be the line across the top of the box. The mitre line, as shown here, is for an octagon, but the system is applicable to any figure from a triangle or rectangle to a polygon with any number of sides. PABT VL-SASHES AND SKYLIGHTS. N the skylight, Fig. 117, of which No. 1 is the plan, and No. 2 the elevation, it is required to find the length and backing of the hip. Let A B be the seat of the hip; erect the perpendicular A C, and make it equal to the vertical height of the skylight, and draw B C, which is the line of the underside of the hip. '" The dotted line g k shows its upper side. No. 2. Fig. 118. To find the backing, from any point in B C, as g: draw perpendicular to B c, a line g v meeting A B in F, and through F draw a line at right angles to A B, meeting the sides of the skylight in D and E. Then from 1 as a centre, and with F g as. radius, cut the line A B in A, and join D A, E A. The angle D h F. is the backing of the hip, and the bevel D A E will give the angle of backing when applied to the perpendicular side of the hip bar. In Fig. 118, in which No. 1 is the plan, and No. 2 the elevation of a skylight with curved bars, to find the hip: let A B be the seat of the centre bar, and De the seat of the hip. Through any divisions 1234c of the r...
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