The Burnside problem and identities in groups S.I. Adian . Ergebnisse der Mathematik und ihrer Grenzgebiete (1932-1942) 95; Ergebnisse der Mathematik und ihrer Grenzgebiete. Neue Folge (1955-) 95; Ergebnisse der Mathematik und ihrer Grenzgebiete Neue Folge 95.

Adân, Sergej Ivanovi?:

ISBN 10: 3540087281 / ISBN 13: 9783540087281

Published by Berlin, Springer, 1979

About this Item

Ex-library with stamp and library-signature. GOOD condition, some traces of use. Ancien Exemplaire de bibliothèque avec signature et cachet. BON état, quelques traces d'usure. Ehem. Bibliotheksexemplar mit Signatur und Stempel. GUTER Zustand, ein paar Gebrauchsspuren. 20 ADI 9783540087281 Sprache: Englisch Gewicht in Gramm: 1150.

Seller Inventory # 2507289

Bibliographic Details

• Title: The Burnside problem and identities in groups S.I. Adian . Ergebnisse der Mathematik und ihrer Grenzgebiete (1932-1942) 95; Ergebnisse der Mathematik und ihrer Grenzgebiete. Neue Folge (1955-) 95; Ergebnisse der Mathematik und ihrer Grenzgebiete Neue Folge 95.
• Publisher: Berlin, Springer
• Publication Date: 1979
• Language: English
• ISBN 10: 3540087281
• ISBN 13: 9783540087281
• Binding: Hardcover
• Weight: 1150 grams
• Seller catalogs:
  • SA MATHEMATIK

About this title

Synopsis

Three years have passed since the publication of the Russian edition of this book, during which time the method described has found new applications. In [26], the author has introduced the concept of the periodic product of two groups. For any two groups G and G without elements of order 2 and for any 1 2 odd n ~ 665, a group G @ Gmay be constructed which possesses several in­ 1 2 teresting properties. In G @ G there are subgroups 6 and 6 isomorphic to 1 2 1 2 G and G respectively, such that 6 and 6 generate G @ G and intersect 1 2 1 2 1 2 in the identity. This operation "@" is commutative, associative and satisfies Mal'cev's postulate (see [27], p. 474), i.e., it has a certain hereditary property for subgroups. For any element x which is not conjugate to an element of either 6 1 or 6 , the relation xn = 1 holds in G @ G • From this it follows that when 2 1 2 G and G are periodic groups of exponent n, so is G @ G • In addition, if G 1 2 1 2 1 and G are free periodic groups of exponent n the group G @ G is also free 2 1 2 periodic with rank equal to the sum of the ranks of G and G • I believe that groups 1 2

Language Notes

Text: English, Russian (translation)